The mass of CaO that would be obtained by heating 20 kg of 90 % pure lime stone is: Options: A . &nbsp11.2kg B . &nbsp8.4kg C . &nbsp10.08kg D . &nbsp16.8kg

Answer: Option C : C Mass of pure limestone = ( 90 100 ) × 20 = 18 k g C a C O 3 Δ − → C a O + C O 2 100 kg of C a C O 3 forms 56 kg of CaO 18 kg of C a C O 3 forms ( 18 × 56 ) 100 = 10.08 kg ofCaO

The mass of CaO that would be obtained by heating 20 kg of 90% pure lime stone i

Question

The mass of CaO that would be obtained by heating 20 kg of

90 %

pure lime stone is:

Options:

A . 11.2kg

B . 8.4kg

C . 10.08kg

D . 16.8kg

Answer: Option C
:
C
Mass of pure limestone =

(\frac{90}{100}) \times 20 = 18 k g

C a C O_{3} Δ - \to C a O + C O_{2}

100 kg of

C a C O_{3}

forms 56 kg of CaO
18 kg of

C a C O_{3}

forms

\frac{(18 \times 56)}{100} = 10.08 kg ofCaO

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