Question
Ordinary water contains one part of heavy water per 6000 parts by weight.The number of heavy water molecules present in a drop of water of volume 0.01 ml is (Density of water is 1 g/ml)
Answer: Option C
:
C
H2O6000 D2O1
0.01 x
x=1×0.016000=1.66×10−6
20gm→6.023×1023
1.66×10−6→x
x=1.66×10−6×6.023×102320=5×1016
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:
C
H2O6000 D2O1
0.01 x
x=1×0.016000=1.66×10−6
20gm→6.023×1023
1.66×10−6→x
x=1.66×10−6×6.023×102320=5×1016
Was this answer helpful ?
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