Calculate the normality of 1.11 gm of CaCl2 is dissolved in 250 ml solution

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Question

Calculate the normality of 1.11 gm of

C a C l_{2}

is dissolved in 250 ml solution.

Options:

A . 0.1 N

B . 0.25 N

C . 0.08 N

D . 0.3 N

Answer: Option C
:
C
Normality =

\frac{N o . o f g r a m e q u i v a l e n t s o f s o l u t e}{V o l u m e o f s o l u t i o n (i n l i t r e)}

equivalent mass =

\frac{M o l e c u l a r M a s s}{V a l e n e c y f a c t o r}

=

\frac{111}{2}

[

{C a}^{+ 0}

\to

{C a}^{2 +}

+

2 e -

] = 55.5
No of gram equivalents =

\frac{1.11}{55.5}

\Rightarrow

Normality =

\frac{\frac{1.11}{55.5}}{\frac{250}{1000}}

= 0.08 N

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