Question
2VO + 3Fe2O3 → 6FeO + V2O5 If we start with 2g of VO and 5.75g of Fe2O3, which is the limiting reagent?
[V = 47.87g] [Fe = 55.85g]
[V = 47.87g] [Fe = 55.85g]
Answer: Option B
:
B
If you check, the reaction is already balanced 2 moles of VO = 3 moles of Fe2O3
2×(47.87+16)=3×(2×55.85+3×16)
2(63.87)g=3×(159.7)g
127.74g of VO = 478.1g of Fe2O3
∴ 2g of VO = 2×478.1127.74=7.50g of Fe2O3
But only 5.75g of Fe2O3 is present.
This Fe2O3 will get used up in the reaction and is the limiting reagent.
Was this answer helpful ?
:
B
If you check, the reaction is already balanced 2 moles of VO = 3 moles of Fe2O3
2×(47.87+16)=3×(2×55.85+3×16)
2(63.87)g=3×(159.7)g
127.74g of VO = 478.1g of Fe2O3
∴ 2g of VO = 2×478.1127.74=7.50g of Fe2O3
But only 5.75g of Fe2O3 is present.
This Fe2O3 will get used up in the reaction and is the limiting reagent.
Was this answer helpful ?
Latest Videos
Latest Test Papers
Submit Solution