Question
Let y=12+13+12+13+..... What is the value of y?
Answer: Option D
:
D
Given : y=12+13+12+13+........
Thus y=12+13+y
y=3+y6+2y+1;⇒2y2+7y=3+y; On solving, y=−3±√152; since the given fraction is positive, the value of y is √15−32
You can also go from elimination of answer options. Answer should
< 0.5 and close to it. This happens only at option (d)
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:
D
Given : y=12+13+12+13+........
Thus y=12+13+y
y=3+y6+2y+1;⇒2y2+7y=3+y; On solving, y=−3±√152; since the given fraction is positive, the value of y is √15−32
You can also go from elimination of answer options. Answer should
< 0.5 and close to it. This happens only at option (d)
Was this answer helpful ?
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