Question
Let g(x)= |x+1|. The number of values that 'x' can take (given that its range is between -2 & + 2 (both inclusive) for which g(x-3), g(x-1), g(x+1) are in AP is?
Answer: Option B
:
B
g(x-3) = |x-2|
g(x-1)=|x|
g(x+1)= |x+2|
These will be in AP if
2|x| = |x-2|+|x+2|
Only x= -2 and x=2 satisfy the above equation in the given range.
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:
B
g(x-3) = |x-2|
g(x-1)=|x|
g(x+1)= |x+2|
These will be in AP if
2|x| = |x-2|+|x+2|
Only x= -2 and x=2 satisfy the above equation in the given range.
Was this answer helpful ?
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