Question
In a game of 100 points, A can give B 20 points and C 28 points. Then, B can give C:
Answer: Option B
$$\eqalign{
& A:B = 100:80 \cr
& A:C = 100:72 \cr
& \therefore \frac{B}{C} = {\frac{B}{A} \times \frac{A}{C}} = {\frac{{80}}{{100}} \times \frac{{100}}{{72}}} \cr
& = \frac{{10}}{9} = \frac{{100}}{{90}} = 100:90 \cr
& \therefore {\text{B}}\,{\text{can}}\,{\text{give}}\,{\text{C}}\,{\text{10}}\,{\text{points}} \cr} $$
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$$\eqalign{
& A:B = 100:80 \cr
& A:C = 100:72 \cr
& \therefore \frac{B}{C} = {\frac{B}{A} \times \frac{A}{C}} = {\frac{{80}}{{100}} \times \frac{{100}}{{72}}} \cr
& = \frac{{10}}{9} = \frac{{100}}{{90}} = 100:90 \cr
& \therefore {\text{B}}\,{\text{can}}\,{\text{give}}\,{\text{C}}\,{\text{10}}\,{\text{points}} \cr} $$
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