Question
In a kilometre race, A, B and C are three participants. A can give B start of 50 m and C a start of 69 m. The start which B can allow C, is -
Answer: Option D
A : B : C = 1000 : (1000 - 50) : (1000 - 69)= 1000 : 950 : 931
In a 950 m race, B can give C a start of (950 - 931) m = 19 m
In a 1000 m race, B can give C a start of = $$\left( {\frac{{19}}{{950}} \times 1000} \right)$$ = 20 m
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A : B : C = 1000 : (1000 - 50) : (1000 - 69)= 1000 : 950 : 931
In a 950 m race, B can give C a start of (950 - 931) m = 19 m
In a 1000 m race, B can give C a start of = $$\left( {\frac{{19}}{{950}} \times 1000} \right)$$ = 20 m
Was this answer helpful ?
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