Question
In a game of 100 points, A can give B 20 points and C 28 points. Then, B can give C:
Answer: Option B
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A : B = 100 : 80.
A : C = 100 : 72.
So, \(\frac{B}{C}=\left(\frac{B}{A}\times\frac{A}{C}\right)=\left(\frac{80}{100}\times\frac{100}{72}\right)=\frac{10}{9}=\frac{100}{90}=100:90.\)
So, B can give C 10 points.
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