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Question

A can run 22.5 m while B runs 25 m. In a kilometre race B beats A by:

Options:
A .  100 m
B .  \(111\frac{1}{9}m\)
C .  25 m
D .  50 m
Answer: Option A

When B runs 25 m, A runs \(\frac{45}{2}m.\)


When B runs 1000 m, A runs \(\left(\frac{45}{2}\times\frac{1}{25}\times1000\right)m=900m.\)


So, B beats A by 100 m.


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