Question
In a 100 m race, A can give B 10 m and C 28 m. In the same race B can give C:
Answer: Option B
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A : B = 100 : 90.
A : C = 100 : 72.
B : C = \(\frac{B}{A}\times\frac{A}{C}=\frac{10}{100}\times\frac{100}{72}=\frac{90}{72}.\)
When B runs 90 m, C runs 72 m. \(\left(\frac{90}{72}\times100\right)m = 80m.\)
When B runs 100 m, C runs
So, B can give C 20 m.
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