Question
A and B take part in 100 m race. A runs at 5 kmph. A gives B a start of 8 m and still beats him by 8 seconds. The speed of B is:
Answer: Option B
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A's speed = \(\left(5\times\frac{5}{18}\right)m/sec = \frac{25}{18}m/sec\)
Time taken by A to cover 100 m = \(\left(100\times\frac{18}{25}\right)m/sec = 72 sec.\)
so, Time taken by B to cover 92 m = (72 + 8) = 80 sec.
B's speed = \(\left(\frac{92}{80}\times\frac{18}{5}\right)kmph =4.14 kmph\)
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