Question
If α and β are the roots of the equation 2x2−3x+4=0, then the equation whose roots are α2 and β2 is
Answer: Option A
:
A
α +β = 32 andαβ = 2
α2+β2=(α+β)2−2αβ=94−4=−74
hence required equation x2−(α2+β2)x+α2β2=0
⇒ x2+74x+4=0⇒ 4x2+7x+16=0
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:
A
α +β = 32 andαβ = 2
α2+β2=(α+β)2−2αβ=94−4=−74
hence required equation x2−(α2+β2)x+α2β2=0
⇒ x2+74x+4=0⇒ 4x2+7x+16=0
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