Question
If 2+i√3 is a root of the equation x2+px+q=0, where p and q are real, then (p, q) =
Answer: Option A
:
A
Since 2+i√3 is a root, therefore 2−i√3 will be other root. Now sum of the roots = 4 = -p and product of roots = 7 = q. Hence (p, q) = (-4, 7).
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:
A
Since 2+i√3 is a root, therefore 2−i√3 will be other root. Now sum of the roots = 4 = -p and product of roots = 7 = q. Hence (p, q) = (-4, 7).
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