Question
If one root of the quadratic equation 2x2+ax−6=0 is 2, find the value of a.
Answer: Option A
:
A
Since, x = 2 is a root of the given equation 2x2+ax−6=0
→ 2(2)2+a×2−6=0
8+2a−6=0
2a=−2
a=−1
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:
A
Since, x = 2 is a root of the given equation 2x2+ax−6=0
→ 2(2)2+a×2−6=0
8+2a−6=0
2a=−2
a=−1
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