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Question
If foci of hyperbola lie on y = x and one of the asymptotes is y = 2x, then equation of the hyperbola, given  that it passes through (3, 4), is
Options:
A .  x2−y2−52xy+5=0
B .  2x2−2y2+5xy+5=0
C .  2x2+2y2−5xy+10=0
D .  Â None of these
Answer: Option C
:
C
Foci of hyperbola lie on y = x. So, the major axis is y = x. Major axis of hyperbola bisects the asymptote.
Equation of hyperbola is x = 2y
Equation of hyperbola is (y – 2x)(x – 2y) + k = 0
Given that, it passes through (3, 4)
Hence, required equation is
2x2+2y25xy+10=0

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