Question
Equation of the chord of the hyperbola 25x2−16y2=400 which is bisected at the point (6, 2), is
Answer: Option B
:
B
Equation of hyperbola is 25x2−16y2=400
⇒ x216−y225=1
Chord is bisected at (6, 2)
∴ 6x16−2y25=6216−2225
⇒ 75x−16y=418
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B
Equation of hyperbola is 25x2−16y2=400
⇒ x216−y225=1
Chord is bisected at (6, 2)
∴ 6x16−2y25=6216−2225
⇒ 75x−16y=418
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