If A = ⎡ ⎢ ⎣ 1 2 3 ⎤ ⎥ ⎦ then AA' = Options: A . &nbsp14 B . &nbsp⎡⎢⎣133⎤⎥⎦ C . &nbsp⎡⎢⎣123246369⎤⎥⎦ D . &nbspNone of these

Answer: Option C : C A' = [1 2 3] therefore AA' = = ⎡ ⎢ ⎣ 1 2 3 ⎤ ⎥ ⎦ [ 1 2 3 ] = ⎡ ⎢ ⎣ 1 2 3 2 4 6 3 6 9 ⎤ ⎥ ⎦

If A=⎡⎢⎣123⎤⎥⎦ then AA' =

Question

A = ⎡ ⎢ ⎣ \begin{matrix} 123 \end{matrix} ⎤ ⎥ ⎦

then AA' =

Options:

A . 14

B . ⎡⎢⎣133⎤⎥⎦

C . ⎡⎢⎣123246369⎤⎥⎦

D . None of these

Answer: Option C
:
C
A' = [1 2 3] therefore AA' =

= ⎡ ⎢ ⎣ \begin{matrix} 123 \end{matrix} ⎤ ⎥ ⎦ [123] = ⎡ ⎢ ⎣ \begin{matrix} 1 & 2 & 3 2 & 4 & 6 3 & 6 & 9 \end{matrix} ⎤ ⎥ ⎦

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