Question
If A=[cosαsinα−sinαcosα], then A2=
Answer: Option C
:
C
SinceA2=A.A=[cosαsinα−sinαcosα][cosαsinα−sinαcosα]=[cos2αsin2α−sin2αcos2α].
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:
C
SinceA2=A.A=[cosαsinα−sinαcosα][cosαsinα−sinαcosα]=[cos2αsin2α−sin2αcos2α].
Was this answer helpful ?
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