If A = [ 4 2 − 1 1 ] and I is the identity matrix of order 2, then (A - 2I)(A - 3I) = Options: A . &nbspI B . &nbsp0 C . &nbsp[1000] D . &nbsp[0001]

Answer: Option B : B ( A − 2 I ) ( A − 3 I ) = [ 2 2 − 1 − 1 ] [ 1 2 − 1 − 2 ] = [ 0 0 0 0 ] = 0

If A=[42−11] and I is the identity matrix of order 2, then (A

Question

A = [\begin{matrix} 4 & 2 - 1 & 1 \end{matrix}]

and I is the identity matrix of order 2, then (A - 2I)(A - 3I) =

Options:

A . I

B . 0

C . [1000]

D . [0001]

Answer: Option B
:
B

(A - 2 I) (A - 3 I) = [\begin{matrix} 2 & 2 - 1 & - 1 \end{matrix}] [\begin{matrix} 1 & 2 - 1 & - 2 \end{matrix}] = [\begin{matrix} 0 & 0 0 & 0 \end{matrix}] = 0

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