Question
Find the area of the triangle with coordinates A(-2, 1), B(3, 3) and C(1, -2).
Answer: Option B
:
B
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B
Area of a triangle having vertices (x1,y1),(x2,y2) and (x3,y3)
=12[x1(y2−y3)+x2(y3−y1)+x3(y1−(y2)]
Given, (x1,y1) = (-2, 1)
(x2,y2) = (3, 3)
(x3,y3) = (1, -2)
=12[−2(3+2)+3(−2−1)+1(1−3)]=−10.5
Since area is not a negative quantity, take the absolute value.
Thus, area of the given triangle = 10.5 sq. units.
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