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Question


The area of a triangle having vertices (a, b+ c), (b, c + a) and (c, a + b) is ___.


Options:
A .   0
B .   1
C .   a + b + c
D .   a2 + b2 + c2
Answer: Option A
:
A

Area of a triangle with vertices (x1,y1),(x2,y2) and (x3,y3) is given by
Area=12×|(x1)(y2y3)+(x2)(y3y1)+(x3)(y1y2)|
Thus, Area of the given triangle 
=12|a(c+aab)+b(a+bbc)+c(b+cca)|
=12|acab+abbc+bcac|=0



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