Question
Answer: Option A
:
A
From the figure, it is evident the required area = AreaofSquare−AreaofCircle4×2
Therefore, required area = [(2)2−π(1)2]4×2=4−π2
Shortcut: 4-pi-2 method
This is the most straightforward example of the circle inside a square pattern.
Therefore, we know that Area of square: Area of Circle = 4:π
Thus,required area = 4−π2
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:
A
From the figure, it is evident the required area = AreaofSquare−AreaofCircle4×2
Therefore, required area = [(2)2−π(1)2]4×2=4−π2
Shortcut: 4-pi-2 method
This is the most straightforward example of the circle inside a square pattern.
Therefore, we know that Area of square: Area of Circle = 4:π
Thus,required area = 4−π2
Was this answer helpful ?
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