Answer: Option A
:
A
Every clock shall display the correct time when it is late or fast by hours which are a multiple of 12 .
As per the question, the first clock loses 3 minutes in an hour. Therefore, to lose 12 hours, it will take $\frac{12\times 60}{3}=240$hours =10 days.
Also, the second clock gains 2 minutes inan hour. Therefore, to gain 12 hours, it will take : $\frac{12\times 60}{2}=360$ hours = 15 days.
Therefore, after 30 days (LCM of 15 and 10), both the watches will show the correct time .