Question
Consider an element ‘Argo’ which forms ccp lattice. Its X-ray studies show that the edge length of its unit cell is 4000 nm. Also the density of Argo is found to be 10 g/cm3. Which of the following elements has the closest atomic mass to that of Argo.
Answer: Option C
:
C
The number of Argo atoms per unit cell(z) = 4
Density (d) = 10g/cm3
Edge length of unit cell (a) = 4000 nm = 4×10−8cm
We know that, d=z×Ma3×NA=>M=d×a3×NAz=10×(4×10−8)3×6.023×10234=96.368 g/mol
This value is closest to the atomic mass of molybdenum.
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:
C
The number of Argo atoms per unit cell(z) = 4
Density (d) = 10g/cm3
Edge length of unit cell (a) = 4000 nm = 4×10−8cm
We know that, d=z×Ma3×NA=>M=d×a3×NAz=10×(4×10−8)3×6.023×10234=96.368 g/mol
This value is closest to the atomic mass of molybdenum.
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