12th Grade > Chemistry
SOLID STATE MCQs
Total Questions : 30
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Answer: Option C. -> Frenkel defect only
:
C
AgBr exhibits Frenkel defect due to large difference in the size of Ag+andBr−ions.
:
C
AgBr exhibits Frenkel defect due to large difference in the size of Ag+andBr−ions.
Answer: Option C. -> Octahedral
:
C
The value of ionic radius ratio is 0.52 which is between 0.414 – 0.732 then the geometrical arrangement of ions in crystal is octahedral.
:
C
The value of ionic radius ratio is 0.52 which is between 0.414 – 0.732 then the geometrical arrangement of ions in crystal is octahedral.
Answer: Option C. -> Large intermolecular distances
:
C
Following are the characteristic features of a solid state:
I.Definite shape, volume and mass
II.Intermolecular distances are short and intermolecular forces are strong
III.They are incompressible and rigid
IV.The constituent particles have fixed positions and can oscillate only about their mean positions
:
C
Following are the characteristic features of a solid state:
I.Definite shape, volume and mass
II.Intermolecular distances are short and intermolecular forces are strong
III.They are incompressible and rigid
IV.The constituent particles have fixed positions and can oscillate only about their mean positions
Answer: Option A. -> 1×10−3mol%
:
A
Each Sr2+ion introduces one cation vacancy
⇒ number of cation vacancies = % mole of Sr2+=10−3mol%
:
A
Each Sr2+ion introduces one cation vacancy
⇒ number of cation vacancies = % mole of Sr2+=10−3mol%
Answer: Option C. -> X4Z3
:
C
Tetrahedral sites are double compared to octahedral sites; and X is present in two-third of them
a) So, ratio of X and Z equals 2×(23):1=4:3
⇒ formula of the compound = X4Z3
:
C
Tetrahedral sites are double compared to octahedral sites; and X is present in two-third of them
a) So, ratio of X and Z equals 2×(23):1=4:3
⇒ formula of the compound = X4Z3
Answer: Option D. -> Schottky defect
:
D
It is stoichiometric imperfection, Crystals having ratio of radius of cation to anion is high
:
D
It is stoichiometric imperfection, Crystals having ratio of radius of cation to anion is high
Answer: Option A. -> n-type semiconductor
:
A
Arsenic has 5 valence electrons; 4 of them take part in covalent bond formation and the remaining one gets delocalized. This gives rise to an electron-rich impurity or n-type semiconductor.
:
A
Arsenic has 5 valence electrons; 4 of them take part in covalent bond formation and the remaining one gets delocalized. This gives rise to an electron-rich impurity or n-type semiconductor.
Answer: Option C. -> ABABA
:
C
ABAB…… is hexagonal close packing
:
C
ABAB…… is hexagonal close packing