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Question 11-12 is based on the following given information:
Assume a hypothetical cubic crystal lattice, named JEE-centered cubic (jcc) with the following characteristics:
I. An atom is present at all the corners of the cube
II. An atom is present at the center of two pairs of opposite faces
III. An atom is present at the center of all the edges of the cube
IV. One atom is present at its body-center
How many atoms are effectively present per unit cell in this hypothetical crystal lattice?
Options:
A .  8
B .  7
C .  6
D .  5
Answer: Option B
:
B
I. 8 corner atom ×(18) atom per unit cell = 1 atom
II. 4 face-centered atoms ×(12)atom per unit cell = 2 atom
III. 12 edge-centered atoms ×(14) atom per unit cell = 3 atom
IV. 1 body centered atom ×1 atom per unit cell = 1 atom
So, Total number of atoms per unit cell =1+2+3+1=7atoms

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