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Question
Calculate 32f(x)dx where
f(x)={6ifx>13x2ifx1
 
Options:
A .  19
B .  21
C .  17
D .  15
Answer: Option B
:
B
Calculate ∫3−2f(x)dx Wheref(x)=6ifx>13x2ifx≤1 
Here, we can see that the integrand f(x) in not continuous in the interval (-2, 3) as it has a discontinuity at x = 1. So we can’t just integrate f(x) and put limits.We’ll have to break this integral into integrals which have limits such that integrands is continuous in those limits.
32f(x)dx=123x2dx+316dx
Now we can integrate these integrands and put limits.
123x2dx+316dx=(x3)|12+(6x)|31=1(8)+186
= 21

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