Question
∫10 x7√1−x4dx is equal to
Answer: Option B
:
B
I=∫10x7√1−x4dx=∫10x6xdx√1−x4
Putx2=sinθ⇒2xdx=cosθdθ
I=12π20sin3θ.cosθdθcosθ=12∫120sin3θdθ
=12T2T(12)2.T(12)=T(12)4.32.12.T(12)=13
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:
B
I=∫10x7√1−x4dx=∫10x6xdx√1−x4
Putx2=sinθ⇒2xdx=cosθdθ
I=12π20sin3θ.cosθdθcosθ=12∫120sin3θdθ
=12T2T(12)2.T(12)=T(12)4.32.12.T(12)=13
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