Question
∫π20 cos x1+sin xdx=
Answer: Option A
:
A
put 1+ sin x =t
Then∫π20cosx1+sinxdx=[log|1+sinx|]π20=log2
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:
A
put 1+ sin x =t
Then∫π20cosx1+sinxdx=[log|1+sinx|]π20=log2
Was this answer helpful ?
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