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Question
An object is placed at a distance of f2 from a convex lens. The image will be formed:
Options:
A .  At −f, virtual and double its size.
B .  At f, real and inverted.
C .  At −2f, virtual and erect.
D .  At 2f, real and erect.
Answer: Option A
:
A
Given u=f2
1f=1v1u
1f=1v+(1f2)1v=1f2f
1v=1f
So v=f i.e., the image will be formed at focus of the lens on the same side as that of the object.
Now magnificationm=vu=ff2=+2
So the image formed will be virtual with magnification +2.

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