In Young’s double slit experiment, the distance between the slits is 0.2

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In Young’s double slit experiment, the distance between the slits is 0.2 mm and the distance of the screen from the slits is 2 m. If light of wavelength 500 nm is used, find the number of fringes formed between two points separated by 1 cm on the screen.

Options:

A . 1

B . 2

C . 3

D . 4

Answer: Option B
:
B

y = n β

Here

β = \frac{λ D}{d} = 0.5 c m

2 fringes.

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