Question
A train 132 m long passes a telegraph pole in 6 seconds. Find the speed of the train?
Answer: Option C
$$\eqalign{
& {\text{Speed}} \cr
& {\text{ = }}\left( {\frac{{132}}{6}} \right){\text{m/sec}} \cr
& {\text{ = }}\left( {22 \times \frac{{18}}{5}} \right){\text{km/sec}} \cr
& {\text{ = 79}}{\text{.2 km/hr}} \cr} $$
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$$\eqalign{
& {\text{Speed}} \cr
& {\text{ = }}\left( {\frac{{132}}{6}} \right){\text{m/sec}} \cr
& {\text{ = }}\left( {22 \times \frac{{18}}{5}} \right){\text{km/sec}} \cr
& {\text{ = 79}}{\text{.2 km/hr}} \cr} $$
Was this answer helpful ?
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