Question
A 280 meter long train crosses a platform thrice its length in 50 seconds. What is the speed of the train in km/hr?
Answer: Option C
$$\eqalign{
& {\text{Length of train}} \cr
& {\text{ = 280 m }} \cr
& {\text{Length of platform}} \cr
& {\text{ = (3}} \times {\text{280) m = 840m}} \cr
& \therefore {\text{Speed of train}} \cr
& {\text{ = }}\left( {\frac{{280 + 840}}{{50}}} \right)m/\sec \cr
& = \frac{{1120}}{{50}}m/\sec \cr
& = \left( {\frac{{1120}}{{50}} \times \frac{{18}}{5}} \right)km/hr \cr
& = 80.64\,km/hr \cr} $$
Was this answer helpful ?
$$\eqalign{
& {\text{Length of train}} \cr
& {\text{ = 280 m }} \cr
& {\text{Length of platform}} \cr
& {\text{ = (3}} \times {\text{280) m = 840m}} \cr
& \therefore {\text{Speed of train}} \cr
& {\text{ = }}\left( {\frac{{280 + 840}}{{50}}} \right)m/\sec \cr
& = \frac{{1120}}{{50}}m/\sec \cr
& = \left( {\frac{{1120}}{{50}} \times \frac{{18}}{5}} \right)km/hr \cr
& = 80.64\,km/hr \cr} $$
Was this answer helpful ?
More Questions on This Topic :
Latest Videos
Latest Test Papers
Submit Solution