Question
A 150 m long train crosses a milestone in 15 seconds and a train of same length coming from the opposite direction in 12 seconds. The speed of the other train is?
Answer: Option D
Speed of first train = $$\frac{{150}}{{15}}$$ m/sec = 10 m/sec
Let the speed of second train be x m/sec
Relative speed = (10 + x) m/sec
∴ $$\frac{{300}}{{10 + {\text{x}}}}$$ = 12
⇒ 300 = 120 + 12x
⇒ 12x = 180
⇒ x = $$\frac{{180}}{{12}}$$ = 15 m/sec
Hence, speed of other train
= $$\left( {15 \times \frac{{18}}{5}} \right)$$ kmph
= 54 kmph
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Speed of first train = $$\frac{{150}}{{15}}$$ m/sec = 10 m/sec
Let the speed of second train be x m/sec
Relative speed = (10 + x) m/sec
∴ $$\frac{{300}}{{10 + {\text{x}}}}$$ = 12
⇒ 300 = 120 + 12x
⇒ 12x = 180
⇒ x = $$\frac{{180}}{{12}}$$ = 15 m/sec
Hence, speed of other train
= $$\left( {15 \times \frac{{18}}{5}} \right)$$ kmph
= 54 kmph
Was this answer helpful ?
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