Question
Two trains, 130 and 110 meters long, are going in the same direction. The faster train takes one minute to pass the other completely. If they are moving in opposite directions, they pass each other completely in 3 seconds. Find the speed of the faster train.
Answer: Option B
Let the speeds of the faster and slower trains be x m/sec and y m/sec respectively.
Then, $$\frac{{240}}{{{\text{x}} - {\text{y}}}}$$ = 60
⇒ x - y = 4 . . . . . . . . (i)
And, $$\frac{{240}}{{{\text{x}} + {\text{y}}}}$$ = 3
⇒ x + y = 80 . . . . . . . . (ii)
Adding (i) and (ii), we get
2x = 84
⇒ x = 42
Putting x = 42 in (i), we get: y = 38
Hence, speed of faster train = 42 m/sec
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Let the speeds of the faster and slower trains be x m/sec and y m/sec respectively.
Then, $$\frac{{240}}{{{\text{x}} - {\text{y}}}}$$ = 60
⇒ x - y = 4 . . . . . . . . (i)
And, $$\frac{{240}}{{{\text{x}} + {\text{y}}}}$$ = 3
⇒ x + y = 80 . . . . . . . . (ii)
Adding (i) and (ii), we get
2x = 84
⇒ x = 42
Putting x = 42 in (i), we get: y = 38
Hence, speed of faster train = 42 m/sec
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