Question
Three taps A, B and C can fill a tank in 12, 15 and 20 hours respectively. If A is open all the time and B and C are open for one hour each alternately, the tank will be full in:
Answer: Option C
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(A + B)'s 1 hour's work = \(\left(\frac{1}{12}+\frac{1}{15}\right)=\frac{9}{60}=\frac{3}{20}\)
A + C)'s hour's work = \(\left(\frac{1}{12}+\frac{1}{20}\right)=\frac{8}{60}=\frac{2}{15}\)
Part filled in 2 hrs =\(\left(\frac{3}{20}+\frac{2}{15}\right)=\frac{17}{60}\)
Part filled in 6 hrs = \(\left(3\times\frac{17}{60}\right) =\frac{17}{20}\)
Remaining part = \(\left(1-\frac{17}{20}\right) =\frac{3}{20}\)
Now, it is the turn of A and B and \(\frac{3}{20}\) part is filled by A and B in 1 hour
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