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Question
A random variable X has the following probability distribution
XP(X=x)XP(X=x)0λ511λ13λ613λ25λ715λ37λ817λ49λ
then, λ is equal to 
 
Options:
A .  181
B .  281
C .  581
D .  781
Answer: Option A
:
A
8x=0P(X)=1P(0)+P(1)+P(2)+P(3)+P(4)+P(5)+P(6)+P(7)+P(8)=1=λ+3λ+5λ+7λ+9λ+11λ+13λ+15λ+17λ=192(λ+17λ)=181λ=1λ=181

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