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Question
A bag contains 3 white, 3 black and 2 red balls.  One by one, three balls are drawn without replacing them.  Then the probability that the third ball is red , is given by
Options:
A .  524
B .  112
C .  14
D .  12
Answer: Option C
:
C
Number of white balls = 3, black balls = 3 red balls = 2
Since drawn balls are not replaced, for third ball to red, we have following patterns:
E1=WWR,BBR,E2=BWR,WBR;andE3=RBR,RWR,BRR,WRR
P(E1)=2×38×27×26,P(E2)=2×38×37×26,P(E3)=4×2×3×18.7.6
Required probability =P(E1)+P(E2)+P(E3)=14

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