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  1. A monkey ascends a greased pole 30 metres in height. He ascends 3 metres in the 1st minute and descends 1 metre in the next minute, again ascends 3 metres in the 3rd minute but descends 1 metre in the 4th minute and so on. In what time does he reach the top?

Options:
A .  \(27\frac{2}{3}\) min
B .  \(28\frac{2}{3}\) min
C .  \(29\frac{2}{3}\)  min
D .  none of these
Answer: Option B

Let the total time taken by the monkey to reach the top of the pole be t minutes.

The total distance covered by the monkey in t minutes can be expressed as:
Distance covered = (3×t) - (1×(t-1))
= 3t - t + 1
= 2t + 1

Since the monkey has to cover a total distance of 30 metres to reach the top of the pole,

2t + 1 = 30
t = 29.5

Therefore, the monkey will take 28 2/3 minutes to reach the top of the pole.

Hence, Option B is the correct answer.

If you think the solution is wrong then please provide your own solution below in the comments section .


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