Answer: Option A
:
A
Number of all possible outcomes = (1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3), (2,4),(2,5),(2,6), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1), (6,2), (6,3), (6,4),(6,5) and (6,6).
The number of all possible outcomes = 36.
There is only one case (5,5) when 5 comes up both the times.
$\text{Probability that 5 will come up both the times}=\frac{\text{Number of times 5 comes up both the times}}{\text{Number of all possible outcomes}}$
$\therefore$ P (5 will come up both the times) =$\frac{1}{36}$