A goldsmith can choose between 3 metals A, B or C to make an artifact. What is t

Sail E0 Webinar

Question

A goldsmith can choose between 3 metals A, B or C to make an artifact. What is the probability that he chooses C?

Options:

A . 13

B . 0

C . 1

D . 23

Answer: Option A
:
A
Since the goldsmith can choose amongst A, B and C, he has 3 possibilities of which the favorable outcome is choosing C. Therefore, probability that he chooses C is

\frac{1}{3}

.

Was this answer helpful ?

Next Question

Submit Solution

More Questions on This Topic :

Question 1. A man is known to speak truth is 75% cases. If he throws an unbiased die and tells his friend that it is a six, th....then the probability that it is actually a six, is

Question 2. A father has three children with at least one boy. The probability that he has two boys and one girl is....

Question 3. One hundred identical coins, each with probability p of showing up heads are tossed once. If 0 < p < 1 ....head showing 51 coins, then the value of p is

Question 4. If (1+4p)4,(1−p)2,and (1−2p)2 are the probabilities of three mutually exclusive events , then the val....mutually exclusive events , then the value of p is

Question 5. Two events A and B have the probabilities 0.25 and 0.5 respectively. The probability that both A and B simultaneou....the probability that neither A and nor B occurs is

Question 6. Seven coupons are selected at random one at a time with replacement from 15 coupons numbered 1 to 15. The probability th....largest number appearing on a selected coupon is 9, is

Question 7. The probabilities of three mutually exclusive events A, B, C are given by 23,14, and 16 respectively. This sta....A, B, C are given by 23,14, and 16 respectively. This statement

Question 8. A random variable X has the following probability distribution XP(X=x)XP(X=x)0λ511λ13λ613λ25....X has the following probability distribution XP(X=x)XP(X=x)0λ511λ13λ613λ25λ715λ37λ817λ49λ then, λ is equal to

Question 9. A fair coin is tossed a fixed number of times. If the probability of getting 7 heads is equal to that gettin....9 heads, then the probability of getting 3 heads is

Question 10. A five digit number is formed with digits 0. 1. 2. 3. 4 without repetition. A number is selected at random, ....then the probability that it is divisible by 4 is

Chapter 1 - GLOBAL STEEL SCENARIO & INDIAN STEEL INDUSTRY Part 1 : (13-04-2024) INDUSTRY AND COMPANY AWARENESS (ICA)

Direction Sense Test Part 1 Reasoning (Hindi)

Chapter 1 - RMHP / OHP / OB & BP Part 1 : (14-02-2024) GPOE

Cube & Cuboid Part 1 Reasoning (Hindi)

Data Interpretation (DI) Basic Concept Reasoning (Hindi)

Counting Figures Part 1 Counting Of Straight Lines Reasoning (Hindi)

Sail E0 free webinar Webinars

Real Numbers Part 7 Class 10 Maths

Real Numbers Part 1 Class 10 Maths

Polynomials Part 1 Class 10 Maths

Chapter 3.1 : Overview of Finance & Accounts Department Chapter 3 : Finance & Accounts SAIL E0 - GFM 2024

Chapter 2.1 : Overview Chapter 2 : Materials Management SAIL E0 - GFM 2024

Chapter 1.1 : Personnel Functions- An overview Chapter 1 : Personnel Management SAIL E0 - GFM 2024

GPOE / GPA Combined 1 Free CBT Mock Test SAIL E0 2024

CBT Mixed Test 1 GPOE/GPA SAIL E0 2024