A can contains a mixture of two liquids A and B is the ratio 7 : 5. When 9 litre

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A can contains a mixture of two liquids A and B is the ratio 7 : 5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7 : 9. How many litres of liquid A was contained by the can initially?

Options:

A . 10

B . 20

C . 21

D . 25

Answer: Option C

Suppose the can initially contains 7x and 5x of mixtures A and B respectively.

Quantity of A in mixture left =

7x -
7
x 9

litres =

7x -
21
litres.
12
4

Quantity of B in mixture left =

5x -
5
x 9

litres =

5x -
15
litres.
12
4

7x -
21

4
=
7

5x -
15
+ 9
4
9

28x - 21
=
7
20x + 21
9

252x - 189 = 140x + 147

112x = 336

x = 3.

So, the can contained 21 litres of A.

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