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All the water in container A which was filled to its brim was poured into two containers B and C. The quantity of water in container B was 62.5% less than the capacity of container A. If 148 liters was now transferred from C to B, then both the containers would have equal quantities of water. What was the initial quantity of water in container A?
Options:
A .  648
B .  888
C .  928
D .  1184
E .  None of these
Answer: Option D


B has 62.5% or (5/8) of the water in A. Therefore, let the quantity of water in container A(initially) be 8k.
Quantity of water in B = 8k - 5k = 3k.Quantity of water in container C = 8k - 3k = 5kContainer:               A   B    CQuantity of water: 8k  3k   5kIt is given that if 148 liters was transferred from container C to container B, then both the containers would have equal quantities of water.5k - 148 = 3k + 148 => 2k = 296 => k = 148The initial quantity of water in A = 8k = 8 * 148 = 1184 liters.



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