A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk

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A milk vendor has 2 cans of milk. The first contains 25% water and the rest milk. The second contains 50% water. How much milk should he mix from each of the containers so as to get 12 litres of milk such that the ratio of water to milk is 3 : 5?

Options:

A . 4 litres, 8 litres

B . 6 litres, 6 litres

C . 5 litres, 7 litres

D . 7 litres, 5 litres

Answer: Option B

Let the cost of 1 litre milk be Re. 1

Milk in 1 litre mix. in 1^st can =
3
litre, C.P. of 1 litre mix. in 1^st can Re.
3
4
4

Milk in 1 litre mix. in 2^nd can =
1
litre, C.P. of 1 litre mix. in 2^nd can Re.
1
2
2

Milk in 1 litre of final mix. =
5
litre, Mean price = Re.
5
8
8

By the rule of alligation, we have:

C.P. of 1 litre mixture in 1^st can
C.P. of 1 litre mixture in 2^nd can
3
4
Mean Price
5
8
1
2
1
8
1
8

Ratio of two mixtures =
1
:
1
= 1 : 1.
8
8

So, quantity of mixture taken from each can =

1
x 12

= 6 litres.
2

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