Question
X and Y can do a piece of work in 20 days and 12 days respectively. X started the work alone and then after 4 days Y joined him till the completion of the work. How long did the work last ?
Answer: Option B
WORK DONE BY X IN 4 DAYS = ( 1/20X 4 ) = 1/5 REMAINING WORK = (1 – 1/5 ) = 4/5 (X + Y)’S 1 DAY’S WORK = 1/20 + 1/12 = 8/60 = 2/15 NOW, 2/15 WORK IS DONE BY X AND Y IN 1 DAY. SO, 4/5 WORK WILL BE DONE BY X AND Y IN 15/2 X 4/5 = 6 DAYS HENCE, TOTAL TIME TAKEN = (6 + 4) DAYS = 10 DAYS.
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WORK DONE BY X IN 4 DAYS = ( 1/20X 4 ) = 1/5 REMAINING WORK = (1 – 1/5 ) = 4/5 (X + Y)’S 1 DAY’S WORK = 1/20 + 1/12 = 8/60 = 2/15 NOW, 2/15 WORK IS DONE BY X AND Y IN 1 DAY. SO, 4/5 WORK WILL BE DONE BY X AND Y IN 15/2 X 4/5 = 6 DAYS HENCE, TOTAL TIME TAKEN = (6 + 4) DAYS = 10 DAYS.
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