Question
A train 110 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
Answer: Option B
$$\eqalign{
& {\text{Speed of train relative to man}} \cr
& {\text{ = }}\left( {60 + 6} \right){\text{km/hr}} \cr
& = 66\,{\text{km/hr}} \cr
& = \left( {66 \times \frac{5}{{18}}} \right)m/\sec \cr
& = \left( {\frac{{55}}{3}} \right)m/\sec \cr
& \therefore {\text{Time taken to pass the man}} \cr
& = \left( {110 \times \frac{3}{{55}}} \right)\sec \cr
& = 6\,\sec \cr} $$
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$$\eqalign{
& {\text{Speed of train relative to man}} \cr
& {\text{ = }}\left( {60 + 6} \right){\text{km/hr}} \cr
& = 66\,{\text{km/hr}} \cr
& = \left( {66 \times \frac{5}{{18}}} \right)m/\sec \cr
& = \left( {\frac{{55}}{3}} \right)m/\sec \cr
& \therefore {\text{Time taken to pass the man}} \cr
& = \left( {110 \times \frac{3}{{55}}} \right)\sec \cr
& = 6\,\sec \cr} $$
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