∫ π 2 − π 2 s i n 2 x d x = Options: A . &nbspπ B . &nbspπ2 C . &nbspπ2−12 D . &nbspπ−1

Answer: Option B : B ∫ π 2 − π 2 s i n 2 x d x = 2 ∫ π 2 0 s i n 2 x d x = 2 r ( 3 2 ) r ( 1 2 ) 2 r ( 2 + 2 2 ) = π 2

∫π2−π2 sin2x dx=

Question

\int_{- \frac{π}{2}}^{\frac{π}{2}} s i n^{2} x d x =

Options:

A . π

B . π2

C . π2−12

D . π−1

Answer: Option B
:
B

\int_{- \frac{π}{2}}^{\frac{π}{2}} s i n^{2} x d x = 2 \int_{0}^{\frac{π}{2}} s i n^{2} x d x = 2 \frac{r (\frac{3}{2}) r (\frac{1}{2})}{2 r (\frac{2 + 2}{2})} = \frac{π}{2}

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