Question
∫√1+3√x3√x2dx is equal to
Answer: Option C
:
C
∫√1+3√x3√x2dx=∫x−23(1+x13)1/2dx
=∫x−2/3(1+x1/3)1/2dx
1+x1/3=t2
x−2/3dx=6tdt
=∫6t2dt
=2t3+c
=2(1+x3)3/2+c
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:
C
∫√1+3√x3√x2dx=∫x−23(1+x13)1/2dx
=∫x−2/3(1+x1/3)1/2dx
1+x1/3=t2
x−2/3dx=6tdt
=∫6t2dt
=2t3+c
=2(1+x3)3/2+c
Was this answer helpful ?
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