Question
Let g(x) be an antiderivative for f(x). Then In (1+(g(x))2) is an antiderivate for
Answer: Option B
:
B
Given ∫f(x)dx=g(x)g′(x)=f(x)
Now ddx(In(1+g2(x))=2g(x)g′(x)1+g2(x)2f(x)g(x)1+g2(x)
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:
B
Given ∫f(x)dx=g(x)g′(x)=f(x)
Now ddx(In(1+g2(x))=2g(x)g′(x)1+g2(x)2f(x)g(x)1+g2(x)
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